This is where The Mole makes a guest appearance... and then stays!
As we mentioned before, ΔH is the energy change in the reaction in KJ/mol .
Fun example (not) :
Measurement of enthalpies of combustion.
This is basically a method identical to that alcohol's investigation!
- Known mass of water placed in beaker (150g)
- Temperature noted (23 ºC)
- Final temperature noted (43ºC)
- Mass of ethanol needed to obtain heat increase (0.9g)
Therefore
Heat gained by water in calorimeter = m x c x DT
= 150g x 4.2 J g-1 K-1 x 20ºC
= 12,600 J Heat produced by burning 0.9g of ethanol = 12.6kJ
A simple calorimeter.
Since 0.9g is 0.9/46 mol ethanol:
Heat produced by burning 1 mol of ethanol = 12.6 kJ / (109/46) kJ mol-1= 644kJ
Therefore DHc [CH3CH2OH] = -644kJ mol-1
Therefore DHc [CH3CH2OH] = -644kJ mol-1
...
In simpler terms, it is how much energy is produced or absorbed in a chemical reaction per 1 mole of the substance.
Example:
If you had 3 moles of Carbon, and the energy produced per one mole is -478 KJ. Then how much energy is produced in total?
-478 KJ X 3 moles = -1434 KJ
1 mole
Notice how the energy is negative; because it was produced, not absorbed!
Example 2:
If you had 349 g of oxygen, then how much energy is absorbed per one mole of oxygen? (energy from the reaction is +234 KJ/mol)
(gotta do some mole calculations here)
grams ---> moles ---> energy
349 g X 1 mole X 234 KJ = 5104 KJ
16.0 g 1 mole