So we learned that there are 6 main mole conversions. So far we have learned only 4.
So what's the other 2?
Mole Conversion type 5:
Atoms to mass:
# of atoms x 1 mole x Mass of atom
6.022 x10^23atom 1 mole
Mole Conversion type 6: (it's the last one =D)
Mass to atoms
Mass # (in the question) x 1 mole x 6.022 x 10^23atoms
Mass of atom 1 mole
This is the finale of types of mole conversion.
To make these kinds of questions "easier", you have to make a plan.
Always try to find the number of moles
See you next time
Wednesday, November 24, 2010
Saturday, November 20, 2010
Mole Conversions
(Yup, there IS such a thing!!)
1) From particles <----> moles
PS, Don't forget sig figs & units..
2) From grams <----> moles
2.04 moles x 12 grams = 24.5 grams of Carbon
1 mole
12 grams
This is what we took so far.. Explain the rest next class!!! :D:D
1) From particles <----> moles
- From particles ---> moles
Ex, 3.01 x 10^24 particles of C ---> mole
3.01 x 10^24 particles X 1 mole = 5.00 moles6.022 x 10^23 particles
PS, Don't forget sig figs & units..
- From moles ---> particles/ molecules/ formula units
Ex, 0.75 moles of CO2 ---> molecules
0.75 moles X 6.022 x 10^23 molecules = 4.5 x 10^23 moleculesmoles
Now, 0.75 moles of CO2 ---> atoms of O24.5 x 10^23 molecules X 2 atoms of O = 9.0 x 10^23 atoms
2) From grams <----> moles
- From moles ---> grams
Ex, 2.04 moles of Carbon ---> gramsmolar mass of Carbon = 12 g / mol
2.04 moles x 12 grams = 24.5 grams of Carbon
1 mole
Ex, 0.341 moles of NO2 ---> grams
molar mass of NO2 = 46.0 g / mol
0.341 moles x 46.0 grams = 15.6 grams of NO21 mole
- From grams ---> moles
Ex,, 3.45 grams of Carbon ---> moles
atomic mass of carbon = 12 grams3.45 grams x 1 mole = 0.288 moles
12 grams
Ex,, 6.2 grams of MgCl2 ---> moles
molecular mass of MgCl2 = 95.3 grams
6.2 grams x 1 mole = 0.065 moles95.3 grams
This is what we took so far.. Explain the rest next class!!! :D:D
THE MOLE
NO! Not the animal, or the TV series, or the body thing!!!!
Soo, What is it then ???
Interesting question!
A MOLE is the amount of pure substance containing the same number of chemical units as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.023 X 10^23).
This involves the acceptance of two dictates -- the scale of atomic masses and the magnitude of the gram.
Its a very huge number used as a relative comparison between substance. So 1 mole of a substance could weight more that 1 mole of a different chemical substance.
Equal volumes of different gases have a constant ratio..
ex,, O2 : H ---> 16 : 1 (16 & 1 are the atomic mass of the 2 elements)
CO2 : H ---> 22 : 1
It gets more interesting..
Avogadro's Number
(Again, the scientific "Avogadro")
Equal volumes of different gases at the same temperature & pressure have the same number of particles. Since they have the same number of particles, the mass ratio is due to the mass of particles.
Avogadro's number indicates that the amount of particles in 1 mole of any substance is
6.022 x 10^23 particles / mole
By the way, relative masses of all atoms is measured in Atomic Mass Unit (aka, AMU)..
Formula Mass
IONIC compounds >> Add AMUs
Ex, Potassium Fluoride
atomic mass of Potassium is 39.1
atomic mass of Fluorine is 19
Therefore, 39.1 + 19 = 58.1 amu
Molecular Mass
COVALENT compounds >> Add Masses
Ex, Carbon Dioxide (CO2)
atomic mass of Carbon is 12
atomic mass of Oxygen is 16
There are 2 atoms of oxygen..
Therefore, 12 + 16 + 16 = 44 amu
Molar Mass
Mass of 1 mole of an element..
Unit >> grams per mole ( g/mol )
Ex, 1 mole of oxygen = 16.0 g/mol
I bet you are saying to yourself,, " myself,, what is the whole point of this??"
I'll tell you what.. IT ALLOWS CHEMISTS TO COUNT ATOMS AND MOLECULES EASIER (yes, it is a big deal!!)..
You've all heard of Mole Day,, (no, not really)...
Well it is on Oct 23rd from 6.02 am till 6.02 pm ..
Check out this Song ::
Thanks for stopping by.. ;)
Sunday, November 14, 2010
Ch.3 Review
Last class, we had a review of chapter 3.
Things to know:
Significant Figures
Measurement and Uncertainty
Scientific Notation
Density
Graphing
Unit Conversion
Good luck on the Test
Things to know:
Significant Figures
Measurement and Uncertainty
Scientific Notation
Density
Graphing
Unit Conversion
Good luck on the Test
Monday, November 8, 2010
Density Graphs
Last class, we went to the computer lab to make a density graph of cold water and hot water.
Thursday, November 4, 2010
LAB 2E!!
Hey
Last class, we did a lab from Essential Experiments for Chemistry!!
We are going to go over what we did.
Our Purpose was to use scienticfic notation and significant figures after determining both volume & density
of an Aluminum sheet.
We measured the length and the width and the mass of the sheet. Then we figured out the density.
Follow up Questions
1. A rectangular metal tray (22.55cm by 15.33cm) plated with thin layerof gold (density: 19.32g/cm3).
Gold plating mass : 0.0538g. Calculate the thinkness using scientific notation and number of sig. figs.
First, write the general formula of density.
D = m
V
Then plug in numbers.
19.32g/cm3 = 0.0538g
V
V = 0.0538g
19.32g/cm3
V = 2.78 x 10-3cm3
Calculate thickness or height
V = LWH
2.78 x 10-3 = 22.55(15.33)H
H = 2.78 x 10-3
22.55(15.33)
H = 8.06 x 10-6cm
2. 1000.0cm3 of oil. Surface area = 850.0m2. Density: 0.850g/cm3
How thick was the oil?
Ok, first there is some irrelevant info here.
Density info is not need because we need to find height or thickness
Therefore, write equation for volume.
V = LWH
Dont forget to convert m to cm
1000.0 = 8.50 x 106(H)
H = 8.50 x 106
1000.0
H = 1.76 x 10-6cm
Thats it for today!
Good nite!
Written by JK Nov 4,2010
Last class, we did a lab from Essential Experiments for Chemistry!!
We are going to go over what we did.
Our Purpose was to use scienticfic notation and significant figures after determining both volume & density
of an Aluminum sheet.
We measured the length and the width and the mass of the sheet. Then we figured out the density.
Follow up Questions
1. A rectangular metal tray (22.55cm by 15.33cm) plated with thin layerof gold (density: 19.32g/cm3).
Gold plating mass : 0.0538g. Calculate the thinkness using scientific notation and number of sig. figs.
First, write the general formula of density.
D = m
V
Then plug in numbers.
19.32g/cm3 = 0.0538g
V
V = 0.0538g
19.32g/cm3
V = 2.78 x 10-3cm3
Calculate thickness or height
V = LWH
2.78 x 10-3 = 22.55(15.33)H
H = 2.78 x 10-3
22.55(15.33)
H = 8.06 x 10-6cm
2. 1000.0cm3 of oil. Surface area = 850.0m2. Density: 0.850g/cm3
How thick was the oil?
Ok, first there is some irrelevant info here.
Density info is not need because we need to find height or thickness
Therefore, write equation for volume.
V = LWH
Dont forget to convert m to cm
1000.0 = 8.50 x 106(H)
H = 8.50 x 106
1000.0
H = 1.76 x 10-6cm
Thats it for today!
Good nite!
Written by JK Nov 4,2010
Tuesday, November 2, 2010
Density!!
Hi everyone!
We are going to teach you about density.
DENSITY is just mass contained in a given volume of a substance.
Before we go on, enjoy this cartoon.
We are going to teach you about density.
DENSITY is just mass contained in a given volume of a substance.
Before we go on, enjoy this cartoon.
Hahaha I hope you are laughing!!
Back to chemistry.
Density is represented by the formula :
Mass(g)
Volume(cm3)
Basically, if density of an object is greater than the density of the liquid then it will sink
If the density of an object is less than the density of the liquid then it will float.
Written by JK (Nov2,2010)
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